NON-HOMOGENEOUS LINEAR ALGEBRAIC EQUATIONS

Non-Homogeneous Systems of Linear Algebraic Equations

A non-homogeneous system of linear equations with an  coefficient matrix consists of  linear equations and  unknown variables, represented as:

Matrix Representation

This system can be compactly expressed in matrix form:

where:

  •  (Coefficient Matrix, ):

  •  (Vector of Unknowns, ):

  •  (Constant Vector, ):

 

Standard Form

where  is an  matrix,  is the vector of unknowns, and  is a non-zero constant vector.

Existence and Types of Solutions

Let  be the augmented matrix,  be the rank of the coefficient matrix, and  be the number of variables:

  • Inconsistent (No Solution):

  • Consistent with a Unique Solution:

  • Consistent with Infinitely Many Solutions:

Problems:

1.     solve the system of linear equations:

sol: Given linear system of non-homogeneous equation

Step 1: Matrix Form & Augmented Matrix

Augmented matrix :

Step 2: finding the Rank of the matrix

Swap Row 1 and Row 3 () to make the leading coefficient 1:

 

Eliminate  from Row 2 and Row 3:

,      

Multiply Row 2 and Row 3 by  (, ):

Eliminate  from Row 3:

   

 

Text Box: █(7(0,5,1,9)&=(0,35,7,63)@5(0,7,3,11)&=(0,35,15,55)@(0,35,7,63)-(0,35,15,55)&=(0,0,-8,8) )Therefore, the =3

Then the System is consistent and system has unique solution.

Step 3: Back-Substitution

Solve for  using Row 3:       

Solve for  using Row 2:               

Solve for  using Row 1:              

2.      solve the system of linear equations

 

sol: Given linear system of non-homogeneous equation

Step 1: Set Up the Augmented Matrix

Step 2: finding the rank of the matrix:

Eliminate  from Row 2 and Row 3:,

 

Eliminate  from Row 3:

Therefore,,

then the system is inconsistent and system has no solution

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3.     solve the system of linear equations:

Sol: Given linear system of non-homogeneous equation

 

Step 1: Set Up the Augmented Matrix

Step 2: Finding the rank of the matrices (Row Operations)

Eliminate  from Row 2 and Row 3:

,

Eliminate  from Row 3:

 

Since,

Then the system is consistent and system has infinitely many solutions.

Step 3: Parametric Solution:
Set
 as a free parameter (, where ).

Solve for  using Row 2:

Solve for  using Row 1:                 

The system has infinitely many solutions parameterized by :

4.     Investigate for what values of λ and μ the equation

 x+y+z=6, x+2y+3z=10, x+2y+λz=μ

then 1. infinite number of solutions

2.unique solution,

3. no solution.

Sol:The system of equations is:     

 

Step 1: Set up the Augmented Matrix

Step 2: Perform Row Operations

Perform  and :

 

Now perform :

 

1. Infinite Number of Solutions

For the system to have infinitely many solutions, the bottom row must consist entirely of zeros, so :[ Infinite solutions: ]

2. Unique Solution

For a unique solution, the third entry in the main diagonal of matrix  must be non-zero, making :[ Unique solution:

3. No Solution

For the system to be inconsistent (no solution), the coefficient part of the bottom row must be zero while the augmented term is non-zero, giving  and :[No solution:

Problems:

1.solve

2.solve

3.

4.solve

5.solve

6. solve 5x+3y+7z=4,3x+26y+2z=9,7x+2y+10z=5 [x= ,y=,z=k]

7.solve

8. Investigate for what values of λ and μ the equation   2x+3y+5z=9, 7x+3y-2z=8, 2x+3y+λz=μ then 1. infinite number of solutions 2. unique solution, 3. no solution. 

                                        [  hint: λ=5 and μ=9]

9. Investigate for what values of a b the equation x + 2y + 3z = 4, x + 3y + 4 = 5, x + 3y + az = b has 1.no solution, 2. a unique solution and 3. an infinite number of solutions [hint: a=4, b=5]


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